4^{3x+1}=6^{1-2x}

Lösung

4^{3 x + 1} = 6^{1 - 2 x}

x = \frac{ln ( \frac{3}{2} )}{2 ln ( 48 )}

Dezimale

x = 0.05236 \dots

Schritte zur Lösung

4^{3 x + 1} = 6^{1 - 2 x}

Wende Exponentenregel an

(3 x + 1) ln (4) = (1 - 2 x) ln (6)

Löse

(3 x + 1) ln (4) = (1 - 2 x) ln (6) : x = \frac{ln ( \frac{3}{2} )}{2 ln ( 48 )}

x = \frac{ln ( \frac{3}{2} )}{2 ln ( 48 )}

5^{x - 9} = 3

1.0 9^{x} = 1.5

4^{- 3 v - 2} = 4^{- v}

e^{12 x} = 2

4 = \frac{1}{2} e^{- 1.2 x}