4^{x+2}=8^{-2x}

Lösung

4^{x + 2} = 8^{- 2 x}

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

4^{x + 2} = 8^{- 2 x}

Wende Exponentenregel an

2 (x + 2) = - 6 x

Löse

2 (x + 2) = - 6 x : x = - \frac{1}{2}

x = - \frac{1}{2}

3^{x} e^{4 x} = e^{7}

2^{2 x + 1} = 3 (2^{x}) - 1

2 7^{x} = 8 1^{x}

x = e^{\frac{1}{2} x - 2}

5^{x^{2} - 1} = 1