9^{6x}=11^{x-3}

Lösung

9^{6 x} = 1 1^{x - 3}

x = - \frac{3 ln ( 11 )}{12 ln ( 3 ) - ln ( 11 )}

Dezimale

x = - 0.66698 \dots

Schritte zur Lösung

9^{6 x} = 1 1^{x - 3}

Wende Exponentenregel an

6 x ln (9) = (x - 3) ln (11)

Löse

6 x ln (9) = (x - 3) ln (11) : x = - \frac{3 ln ( 11 )}{12 ln ( 3 ) - ln ( 11 )}

x = - \frac{3 ln ( 11 )}{12 ln ( 3 ) - ln ( 11 )}

x^{x} = 5^{\frac{2}{25}}

2^{x} = 5^{x - 2}

2 (10)^{x} + 1 0^{x + 1} = 4

67 = 2 1^{x}

so l v e f or y = b + a e^{- x}, x