e^{4x}e^{-2x+1}=2

Lösung

e^{4 x} e^{- 2 x + 1} = 2

x = \frac{ln ( 2 ) - 1}{2}

Dezimale

x = - 0.15342 \dots

Schritte zur Lösung

e^{4 x} e^{- 2 x + 1} = 2

Wende Exponentenregel an

4 x - 2 x + 1 = ln (2)

Löse

4 x - 2 x + 1 = ln (2) : x = \frac{ln ( 2 ) - 1}{2}

x = \frac{ln ( 2 ) - 1}{2}

5^{2 x - 1} = 0

1240000 = 525600 e^{0.03 t}

e^{2 x} + 2 x e^{2 x} = 0

\frac{3 x + 16}{2 ^{x}} = 0

3^{2 x + 1} = 2^{x}