16*4^{x-2}=8^{x^2-x}

Lösung

16 \cdot 4^{x - 2} = 8^{x^{2} - x}

x = \frac{5}{3}, x = 0

Dezimale

x = 1.66666 \dots, x = 0

Schritte zur Lösung

16 \cdot 4^{x - 2} = 8^{x^{2} - x}

Wende Exponentenregel an

2 (x - 2) + 4 = 3 (x^{2} - x)

Löse

2 (x - 2) + 4 = 3 (x^{2} - x) : x = \frac{5}{3}, x = 0

x = \frac{5}{3}, x = 0

4 (1.2)^{x} = 36

e^{3 x + 2} = 1

2^{x + 1} = 256

6 4^{x} = \frac{1}{2}

2^{(3 x^{3} + 11 x^{2} - 4 x)} = 1