3^{2x^2+3x-2}=1

Lösung

3^{2 x^{2} + 3 x - 2} = 1

x = \frac{1}{2}, x = - 2

Dezimale

x = 0.5, x = - 2

Schritte zur Lösung

3^{2 x^{2} + 3 x - 2} = 1

Wende Exponentenregel an

(2 x^{2} + 3 x - 2) ln (3) = ln (1)

Löse

(2 x^{2} + 3 x - 2) ln (3) = ln (1) : x = \frac{1}{2}, x = - 2

x = \frac{1}{2}, x = - 2

8 1^{x^{2} - 1} = 2 7^{- (7 - 5 x)}

2^{r} = (\frac{1}{3})^{r - 1}

10 = 2^{\frac{t}{3}}

2 = 1. 2^{x}

5^{5 x + 2} = 15