12^{x^2+2x+3}=1728

Lösung

1 2^{x^{2} + 2 x + 3} = 1728

x = 0, x = - 2

Schritte zur Lösung

1 2^{x^{2} + 2 x + 3} = 1728

Wende Exponentenregel an

x^{2} + 2 x + 3 = 3

Löse

x^{2} + 2 x + 3 = 3 : x = 0, x = - 2

x = 0, x = - 2

2^{2 x} = \frac{1}{8}

e^{- x} + 2 x - 1 = 0

2^{8^{x - 2}} = 4^{4^{x - 1}}

4^{2 x + 1} - 65 (4^{x}) + 16 = 0

e^{(9 x)} - 5 e^{(3 x)} + 4 = 0