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Beliebt Algebra >

sqrt(2^{3x+5)}=9^{x+1}

Lösung

2^{3 x + 5} = 9^{x + 1}

Lösung

x = \frac{4 ln ( 3 ) - 5 ln ( 2 )}{3 ln ( 2 ) - 4 ln ( 3 )}

+1

Dezimale

x = - 0.40117 \dots

Schritte zur Lösung

2^{3 x + 5} = 9^{x + 1}

Wende Exponentenregel an

(3 x + 5) \frac{1}{2} ln (2) = (x + 1) ln (9)

Löse

(3 x + 5) \frac{1}{2} ln (2) = (x + 1) ln (9) : x = \frac{4 ln ( 3 ) - 5 ln ( 2 )}{3 ln ( 2 ) - 4 ln ( 3 )}

x = \frac{4 ln ( 3 ) - 5 ln ( 2 )}{3 ln ( 2 ) - 4 ln ( 3 )}

Graph

Beliebte Beispiele

2^{x} = 8^{x + 2}

(0.5)^x-2^x-(0.5)^{2x+3}=1

(0.5)^{x} - 2^{x} - (0.5)^{2 x + 3} = 1

(sqrt(x))^x=(x)^{sqrt(x)}

(x)^{x} = (x)^{x}

3^{2x-1}=7^{x-1}

3^{2 x - 1} = 7^{x - 1}

(x-1)^{(x-1)}=27

(x - 1)^{(x - 1)} = 27