solvefor y,x=3^{y+1}

Lösung

löse nach

y, x = 3^{y + 1}

y = \frac{ln ( x )}{ln ( 3 )} - 1

Schritte zur Lösung

x = 3^{y + 1}

Wende Exponentenregel an

ln (x) = (y + 1) ln (3)

Löse

ln (x) = (y + 1) ln (3) : y = \frac{ln ( x )}{ln ( 3 )} - 1

y = \frac{ln ( x )}{ln ( 3 )} - 1

3^{x + 1} = 7^{x}

2^{5 x + 3} = 10

3^{x - 1} = 5

(b^{2 x - 5})^{4} = (b^{x + 5})^{3}

10 0^{x} = 10