3^{2x+1}=9

Lösung

3^{2 x + 1} = 9

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

3^{2 x + 1} = 9

Wende Exponentenregel an

2 x + 1 = 2

Löse

2 x + 1 = 2 : x = \frac{1}{2}

x = \frac{1}{2}

so l v e f or x, 2^{x + y} = 1

so l v e f or y, 7^{x - 1} = e^{y}

2^{x} + 4^{x} = 20

2^{x + 1} + 2^{2 - x} = 9

4^{3 x - 1} = \frac{1}{8 ^{x - 1}}