2^{x+1}=6

Lösung

2^{x + 1} = 6

x = \frac{ln ( 6 )}{ln ( 2 )} - 1

Dezimale

x = 1.58496 \dots

Schritte zur Lösung

2^{x + 1} = 6

Wende Exponentenregel an

(x + 1) ln (2) = ln (6)

Löse

(x + 1) ln (2) = ln (6) : x = \frac{ln ( 6 )}{ln ( 2 )} - 1

x = \frac{ln ( 6 )}{ln ( 2 )} - 1

\frac{1}{128} = 2^{5 x + 3}

2 7^{x} (9^{2 x - 1}) = 3^{x + 4}

2^{8 x + 3} = 2

\frac{27}{9 ^{x}} = 3^{x - 1}

3 6^{2 x - 7} = 6^{x - 5}