3^{x-5}=2

Lösung

3^{x - 5} = 2

x = \frac{ln ( 2 )}{ln ( 3 )} + 5

Dezimale

x = 5.63092 \dots

Schritte zur Lösung

3^{x - 5} = 2

Wende Exponentenregel an

(x - 5) ln (3) = ln (2)

Löse

(x - 5) ln (3) = ln (2) : x = \frac{ln ( 2 )}{ln ( 3 )} + 5

x = \frac{ln ( 2 )}{ln ( 3 )} + 5

so l v e f or x, ln (y) = e^{x} + c

\frac{1}{25} = 5^{x}

7 e^{- 0.2 t} = 28

8^{2 x - 1} = 3^{x - 2}

3^{2 x + 1} - 4 (3^{3 x + 1}) + 1 = 0