4^{x-1}=3

Lösung

4^{x - 1} = 3

x = \frac{ln ( 3 )}{2 ln ( 2 )} + 1

Dezimale

x = 1.79248 \dots

Schritte zur Lösung

4^{x - 1} = 3

Wende Exponentenregel an

(x - 1) ln (4) = ln (3)

Löse

(x - 1) ln (4) = ln (3) : x = \frac{ln ( 3 )}{2 ln ( 2 )} + 1

x = \frac{ln ( 3 )}{2 ln ( 2 )} + 1

x^{7} = 7^{x}

e^{1 - 2 x} = e^{3 x - 5}

8^{2 x + 3} = 2^{a} b^{x}

e^{5 l n (x)} = 32

(5)^{3 x - 1} = 4