8^{x+1}=43

Lösung

8^{x + 1} = 43

x = \frac{ln ( 43 )}{3 ln ( 2 )} - 1

Dezimale

x = 0.80875 \dots

Schritte zur Lösung

8^{x + 1} = 43

Wende Exponentenregel an

(x + 1) ln (8) = ln (43)

Löse

(x + 1) ln (8) = ln (43) : x = \frac{ln ( 43 )}{3 ln ( 2 )} - 1

x = \frac{ln ( 43 )}{3 ln ( 2 )} - 1

4^{x - 1} = 2^{x + 2}

3^{x} = 527

2^{5 x + 15} = 4^{10 x + 5}

e^{0.05 x} = 3

5 0^{x} = 2