(1+0.01)^x=2

解答

(1 + 0.01)^{x} = 2

x = \frac{ln ( 2 )}{ln ( 1.01 )}

十进制

x = 69.66071 \dots

求解步骤

(1 + 0.01)^{x} = 2

使用指数运算法则

x ln (1 + 0.01) = ln (2)

解

x ln (1 + 0.01) = ln (2) : x = \frac{ln ( 2 )}{ln ( 1.01 )}

x = \frac{ln ( 2 )}{ln ( 1.01 )}

1200 = 500 e^{k}

6 4^{2 x - 5} = 2^{3 - 7 x}

3^{2 x} = 9^{- 2 x - 18}

9^{x - 4} = 7^{- 3 x}

3^{x} + 3^{x + 2} = \frac{10}{3}