a^{x+2}=b

Lösung

a^{x + 2} = b

x = \frac{ln ( b )}{ln ( a )} - 2

Schritte zur Lösung

a^{x + 2} = b

Wende Exponentenregel an

(x + 2) ln (a) = ln (b)

Löse

(x + 2) ln (a) = ln (b) : x = \frac{ln ( b )}{ln ( a )} - 2

x = \frac{ln ( b )}{ln ( a )} - 2

2^{x - 3} = 32

so l v e f or t, x = e^{- 2 t}

1 6^{2 x} = 8^{3 x}

4^{x} - 9 (2^{x}) + 8 = 0

e^{2 x} = - 1