3^{2x}*2^x= 1/18

Lösung

3^{2 x} \cdot 2^{x} = \frac{1}{18}

x = - 1

Schritte zur Lösung

3^{2 x} \cdot 2^{x} = \frac{1}{18}

Wende Exponentenregel an

(lo g_{2} (3) \cdot 2 x + x) ln (2) = ln (\frac{1}{18})

Löse

(lo g_{2} (3) \cdot 2 x + x) ln (2) = ln (\frac{1}{18}) : x = - 1

x = - 1

2^{x} 3^{x + 1} = 108

(5 - e)^{x} = 1

7 = 2^{x}

3 e^{2 x} = 4

(3 π)^{p} = 27 π^{3}