2^{2x-2}=20

Lösung

2^{2 x - 2} = 20

x = \frac{ln ( 80 )}{2 ln ( 2 )}

Dezimale

x = 3.16096 \dots

Schritte zur Lösung

2^{2 x - 2} = 20

Wende Exponentenregel an

(2 x - 2) ln (2) = ln (20)

Löse

(2 x - 2) ln (2) = ln (20) : x = \frac{ln ( 80 )}{2 ln ( 2 )}

x = \frac{ln ( 80 )}{2 ln ( 2 )}

4^{- 2 m - 1} = 4^{2 m}

e^{x + 1} = e^{2 - x}

so l v e f or z, 3^{x} = 4^{y} = 1 2^{z}

2^{2 x - 1} - 9 \cdot 2^{x - 2} + 1 = 0

e^{2 x} + 3 e^{x} = 10