27^{9x+4}*3^{x-8}=3^{x+9}

Lösung

2 7^{9 x + 4} \cdot 3^{x - 8} = 3^{x + 9}

x = \frac{5}{27}

Dezimale

x = 0.18518 \dots

Schritte zur Lösung

2 7^{9 x + 4} \cdot 3^{x - 8} = 3^{x + 9}

Wende Exponentenregel an

3 (9 x + 4) + x - 8 = x + 9

Löse

3 (9 x + 4) + x - 8 = x + 9 : x = \frac{5}{27}

x = \frac{5}{27}

2^{x} - 1 = 0

e^{2 x} = e^{x}

3^{x^{3}} = 9^{x}

2 e^{x} - e^{- 3 x} = 0

0.7 5^{x} = \frac{9}{16}