8^{2x+1}=4^{1-x}

Lösung

8^{2 x + 1} = 4^{1 - x}

x = - \frac{1}{8}

Dezimale

x = - 0.125

Schritte zur Lösung

8^{2 x + 1} = 4^{1 - x}

Wende Exponentenregel an

3 (2 x + 1) = 2 (1 - x)

Löse

3 (2 x + 1) = 2 (1 - x) : x = - \frac{1}{8}

x = - \frac{1}{8}

e^{x^{2} + 2} = 57

9^{x} = 2 7^{2 - 2 x}

e^{x - 1} = e^{2 (x + 1)}

4^{x - 1} + 2^{x + 2} = 48

(\frac{1}{2})^{3 a} = 2^{3 a + 3}