e^{x-1}=e^{2(x+1)}

Lösung

e^{x - 1} = e^{2 (x + 1)}

x = - 3

Schritte zur Lösung

e^{x - 1} = e^{2 (x + 1)}

Wende Exponentenregel an

x - 1 = 2 (x + 1)

Löse

x - 1 = 2 (x + 1) : x = - 3

x = - 3

4^{x - 1} + 2^{x + 2} = 48

(\frac{1}{2})^{3 a} = 2^{3 a + 3}

2^{x - 2} = \frac{8}{2 ^{x - 3}}

5^{2 x} - 6 \cdot 5^{x} + 5 = 0

(\frac{1}{2})^{x} = 16