49^{x+3}=7^{x^2-3x-8}

Lösung

4 9^{x + 3} = 7^{x^{2} - 3 x - 8}

x = 7, x = - 2

Schritte zur Lösung

4 9^{x + 3} = 7^{x^{2} - 3 x - 8}

Wende Exponentenregel an

2 (x + 3) = x^{2} - 3 x - 8

Löse

2 (x + 3) = x^{2} - 3 x - 8 : x = 7, x = - 2

x = 7, x = - 2

1 + 9^{x} = 3^{x + 1} + 3^{x - 1}

\frac{9 ^{x}}{9 ^{3}} = 9^{5}

6^{x} = 12

3^{x + 1} = 8

1 9^{x} = 0