4^{log_{4}(x)+log_{4}(2)}=3

Lösung

4^{l o g_{4} (x) + l o g_{4} (2)} = 3

x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

Dezimale

x = 1.5

Schritte zur Lösung

4^{l o g_{4} (x) + l o g_{4} (2)} = 3

Wende Exponentenregel an

(lo g_{4} (x) + lo g_{4} (2)) ln (4) = ln (3)

Löse

(lo g_{4} (x) + lo g_{4} (2)) ln (4) = ln (3) : x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

5^{x} = 30

9^{x} = (\frac{1}{27})^{x - 2}

9^{x + 1} = 2 7^{3 x - 4}

5^{2 x} = 2 5^{4 - x}

2 e^{x} = 110