2^{x+1}=5^{1-2x}

Lösung

2^{x + 1} = 5^{1 - 2 x}

x = \frac{ln ( 5 ) - ln ( 2 )}{ln ( 50 )}

Dezimale

x = 0.23422 \dots

Schritte zur Lösung

2^{x + 1} = 5^{1 - 2 x}

Wende Exponentenregel an

(x + 1) ln (2) = (1 - 2 x) ln (5)

Löse

(x + 1) ln (2) = (1 - 2 x) ln (5) : x = \frac{ln ( 5 ) - ln ( 2 )}{ln ( 50 )}

x = \frac{ln ( 5 ) - ln ( 2 )}{ln ( 50 )}

8 1^{x} = 3

2 5^{x} = \frac{e}{5 ^{3 x}}

7 2^{3 x - 1} = 32

2^{3 x} = 10

3^{x} = 10