2^{x+2}=16

Lösung

2^{x + 2} = 16

x = 2

Schritte zur Lösung

2^{x + 2} = 16

Wende Exponentenregel an

x + 2 = 4

Löse

x + 2 = 4 : x = 2

x = 2

e^{2 x} = 4

4^{1 - x} = 3^{2 x + 3}

ln (2 e^{x} + 1) = - 1

e^{2 x} - 4 = 0

2^{x + 1} + 5 \cdot 2^{x} = 28