(AX+B)/X =(CX)/D

解答

\frac{A X + B}{X} = \frac{CX}{D}

X = \frac{A D + A ^{2} D ^{2} + 4 BC D}{2 C}, X = \frac{A D - A ^{2} D ^{2} + 4 BC D}{2 C}; D \neq = 0, C \neq = 0

求解步骤

\frac{A X + B}{X} = \frac{CX}{D}

使用分式交叉相乘

(A X + B) D = C X^{2}; D \neq = 0

解

(A X + B) D = C X^{2} : X = \frac{A D + A ^{2} D ^{2} + 4 BC D}{2 C}, X = \frac{A D - A ^{2} D ^{2} + 4 BC D}{2 C}; C \neq = 0

X = \frac{A D + A ^{2} D ^{2} + 4 BC D}{2 C}, X = \frac{A D - A ^{2} D ^{2} + 4 BC D}{2 C}; D \neq = 0, C \neq = 0

\frac{750}{x - 750} = 2.083

(x) = \frac{1}{( x - 3 )}

\frac{2}{x} - \frac{5}{x + 2} = 1

\frac{x + 1}{3} = \frac{x + 5}{x}

\frac{3}{c} = - \frac{9}{64}