((n+2)!)/((n-1)!)=30n

Lösung

\frac{( n + 2 ) !}{( n - 1 ) !} = 30 n

n = 0, n = 4, n = - 7

Schritte zur Lösung

\frac{( n + 2 ) !}{( n - 1 ) !} = 30 n

Vereinfache

\frac{( n + 2 ) !}{( n - 1 ) !} : n (n + 2) (n + 1)

n (n + 2) (n + 1) = 30 n

Löse

n (n + 2) (n + 1) = 30 n : n = 0, n = 4, n = - 7

n = 0, n = 4, n = - 7

\frac{( 2 x + 1 ) ( x - 1 )}{( x + 1 )} = 0

\frac{6}{12} = \frac{2}{n}

so l v e f or a, hb + 5 = \frac{- b}{2 a}

2 x - 4 x^{- 1} = 7

x^{2} + \frac{5}{x ^{2}} = 6