(x)=(x^2-5x+6)/(x^2-4)

解答

(x) = \frac{x ^{2} - 5 x + 6}{x ^{2} - 4}

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

求解步骤

(x) = \frac{x ^{2} - 5 x + 6}{x ^{2} - 4}

化简

\frac{x ^{2} - 5 x + 6}{x ^{2} - 4} : \frac{x - 3}{x + 2}

(x) = \frac{x - 3}{x + 2}

在两边乘以

x + 2

x (x + 2) = x - 3

解

x (x + 2) = x - 3 : x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

\frac{x ^{2}}{x ^{2} - 4} = 0

\frac{39}{x} = 13

so l v e f or f, h = \frac{k - g}{f - 7}

2 x^{- 2} - 11 x^{- 1} - 6 = 0

2 x^{- 2} - 9 x^{- 1} - 5 = 0