1/x =a^2

解答

\frac{1}{x} = a^{2}

x = \frac{1}{a ^{2}}; a \neq = 0

求解步骤

\frac{1}{x} = a^{2}

在两边乘以

x

1 = a^{2} x

交换两边

a^{2} x = 1

两边除以

a^{2}; a \neq = 0

x = \frac{1}{a ^{2}}; a \neq = 0

- 50 = \frac{1}{2 ( - 9.8 ) x ^{2}}

so l v e f or D, 8 = \frac{b}{D}

\frac{4}{x} = - \frac{2}{19}

\frac{6}{4 y + 1} = \frac{9}{9 y - 6}

\frac{1}{x - 2} = 3