y=|2|

Lösung

y = ∣ 2 ∣

y = 2

Schritte zur Lösung

y = ∣ 2 ∣

Wende Absoluteregel an:

∣ a ∣ = a, a \geq 0

y = 2

f = 2 (1) + 3

2 x - 3 - (x + 1) = - [x + 3 (x + 2)] - (x + 4)

y + 3 = 17

\frac{x}{4} = \frac{9}{12}

lo g_{4} (64) = \frac{( 2 x - 1 )}{3}