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人気のある代数 >

solvefor x,(x+y_{i})^2=3-4i

解

解く

x, (x + y_{i})^{2} = 3 - 4 i

解

x = - y_{i} + 2 - i, x = - y_{i} - 2 + i

解答ステップ

(x + y_{i})^{2} = 3 - 4 i

拡張

(x + y_{i})^{2} : x^{2} + 2 x y_{i} + (y_{i})^{2}

x^{2} + 2 x y_{i} + (y_{i})^{2} = 3 - 4 i

両辺から

3 - 4 i

を引く

x^{2} + 2 x y_{i} + (y_{i})^{2} - (3 - 4 i) = 3 - 4 i - (3 - 4 i)

簡素化

x^{2} + 2 y_{i} x + (y_{i})^{2} - 3 + 4 i = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 y _{i} \pm ( 2 y _{i} ) ^{2} - 4 \cdot 1 \cdot ( ( y _{i} ) ^{2} - 3 + 4 i )}{2 \cdot 1}

簡素化

(2 y_{i})^{2} - 4 \cdot 1 \cdot ((y_{i})^{2} - 3 + 4 i) : 4 - 2 i

x_{1, 2} = \frac{- 2 y _{i} \pm ( 4 - 2 i )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 2 y _{i} + 4 - 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 y _{i} - ( 4 - 2 i )}{2 \cdot 1}

x = \frac{- 2 y _{i} + 4 - 2 i}{2 \cdot 1} : - y_{i} + 2 - i

x = \frac{- 2 y _{i} - ( 4 - 2 i )}{2 \cdot 1} : - y_{i} - 2 + i

二次equationの解:

x = - y_{i} + 2 - i, x = - y_{i} - 2 + i

人気の例

solvefor x,4x^2+9x+3=0

so l v e f or x, 4 x^{2} + 9 x + 3 = 0

2 x^{2} - 3 x + \frac{5}{8} = 0

5x^2-3x+1=-3x^2-2x

5 x^{2} - 3 x + 1 = - 3 x^{2} - 2 x

a^{2} + 24 a + 144 = 0

5 x^{2} - 50 x + 30 = 0