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人気のある代数 >

solvefor x,f(x-2)f=x^2+5

解

解く

x, f (x - 2) f = x^{2} + 5

解

x = \frac{f ^{2} + f ^{4} - 4 ( 5 + 2 f ^{2} )}{2}, x = \frac{f ^{2} - f ^{4} - 4 ( 5 + 2 f ^{2} )}{2}

解答ステップ

f (x - 2) f = x^{2} + 5

拡張

f (x - 2) f : x f^{2} - 2 f^{2}

x f^{2} - 2 f^{2} = x^{2} + 5

辺を交換する

x^{2} + 5 = x f^{2} - 2 f^{2}

両辺から

x f^{2} - 2 f^{2}

を引く

x^{2} + 5 - (x f^{2} - 2 f^{2}) = x f^{2} - 2 f^{2} - (x f^{2} - 2 f^{2})

簡素化

x^{2} - f^{2} x + 5 + 2 f^{2} = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - f ^{2} ) \pm ( - f ^{2} ) ^{2} - 4 \cdot 1 \cdot ( 5 + 2 f ^{2} )}{2 \cdot 1}

簡素化

(- f^{2})^{2} - 4 \cdot 1 \cdot (5 + 2 f^{2}) : f^{4} - 4 (5 + 2 f^{2})

x_{1, 2} = \frac{- ( - f ^{2} ) \pm f ^{4} - 4 ( 5 + 2 f ^{2} )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - f ^{2} ) + f ^{4} - 4 ( 5 + 2 f ^{2} )}{2 \cdot 1}, x_{2} = \frac{- ( - f ^{2} ) - f ^{4} - 4 ( 5 + 2 f ^{2} )}{2 \cdot 1}

x = \frac{- ( - f ^{2} ) + f ^{4} - 4 ( 5 + 2 f ^{2} )}{2 \cdot 1} : \frac{f ^{2} + f ^{4} - 4 ( 5 + 2 f ^{2} )}{2}

x = \frac{- ( - f ^{2} ) - f ^{4} - 4 ( 5 + 2 f ^{2} )}{2 \cdot 1} : \frac{f ^{2} - f ^{4} - 4 ( 5 + 2 f ^{2} )}{2}

二次equationの解:

x = \frac{f ^{2} + f ^{4} - 4 ( 5 + 2 f ^{2} )}{2}, x = \frac{f ^{2} - f ^{4} - 4 ( 5 + 2 f ^{2} )}{2}

グラフ

人気の例

10 = x^{2} - 4 x + 1

b x^{2} + b x - x = 0

x^{2} - 9 x = 4

x^{2} = 6 x + 4

x^{2} - 18 x - 11 = 0