c^2-15c+54=0

解

c^{2} - 15 c + 54 = 0

c = 9, c = 6

解答ステップ

c^{2} - 15 c + 54 = 0

解くとthe二次式

c_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

c_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

解を分離する

c_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, c_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

c = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

c = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

二次equationの解:

c = 9, c = 6