zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

solvefor x,f(x+h)=3x^2+4x-2

解答

求解

x, f (x + h) = 3 x^{2} + 4 x - 2

解答

x = \frac{- 4 + f + f ^{2} + 12 h f - 8 f + 40}{6}, x = \frac{- 4 + f - f ^{2} + 12 h f - 8 f + 40}{6}

求解步骤

f (x + h) = 3 x^{2} + 4 x - 2

展开

f (x + h) : x f + h f

x f + h f = 3 x^{2} + 4 x - 2

交换两边

3 x^{2} + 4 x - 2 = x f + h f

将

h f

para o lado esquerdo

3 x^{2} + 4 x - 2 - h f = x f

将

x f

para o lado esquerdo

3 x^{2} + 4 x - 2 - h f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

3 x^{2} + (4 - f) x - 2 - h f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 4 - f ) \pm ( 4 - f ) ^{2} - 4 \cdot 3 ( - 2 - h f )}{2 \cdot 3}

化简

(4 - f)^{2} - 4 \cdot 3 (- 2 - h f) : f^{2} + 12 h f - 8 f + 40

x_{1, 2} = \frac{- ( 4 - f ) \pm f ^{2} + 12 h f - 8 f + 40}{2 \cdot 3}

将解分隔开

x_{1} = \frac{- ( 4 - f ) + f ^{2} + 12 h f - 8 f + 40}{2 \cdot 3}, x_{2} = \frac{- ( 4 - f ) - f ^{2} + 12 h f - 8 f + 40}{2 \cdot 3}

x = \frac{- ( 4 - f ) + f ^{2} + 12 h f - 8 f + 40}{2 \cdot 3} : \frac{- 4 + f + f ^{2} + 12 h f - 8 f + 40}{6}

x = \frac{- ( 4 - f ) - f ^{2} + 12 h f - 8 f + 40}{2 \cdot 3} : \frac{- 4 + f - f ^{2} + 12 h f - 8 f + 40}{6}

二次方程组的解是:

x = \frac{- 4 + f + f ^{2} + 12 h f - 8 f + 40}{6}, x = \frac{- 4 + f - f ^{2} + 12 h f - 8 f + 40}{6}

作图

流行的例子

solvefor x,(y-x-2)^2=9x

so l v e f or x, (y - x - 2)^{2} = 9 x

(1+x)^2-1=100x^2

(1 + x)^{2} - 1 = 100 x^{2}

6(x-12)(x-8)=840

6 (x - 12) (x - 8) = 840

2 x^{2} - 19 x + 42 = 0

x^{2} - 3 (x + 4) = - 2 x