a^2-10a+16=0

解

a^{2} - 10 a + 16 = 0

a = 8, a = 2

解答ステップ

a^{2} - 10 a + 16 = 0

解くとthe二次式

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

a_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

解を分離する

a_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, a_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

a = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

a = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

二次equationの解:

a = 8, a = 2