6c^2+12c=0

解

6 c^{2} + 12 c = 0

c = 0, c = - 2

解答ステップ

6 c^{2} + 12 c = 0

解くとthe二次式

c_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 \cdot 0 = 12

c_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 6}

解を分離する

c_{1} = \frac{- 12 + 12}{2 \cdot 6}, c_{2} = \frac{- 12 - 12}{2 \cdot 6}

c = \frac{- 12 + 12}{2 \cdot 6} : 0

c = \frac{- 12 - 12}{2 \cdot 6} : - 2

二次equationの解:

c = 0, c = - 2