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受欢迎的代数 >

21k^2+4k=-3+6k+9k^2

解答

21 k^{2} + 4 k = - 3 + 6 k + 9 k^{2}

解答

k = \frac{1}{12} - i \frac{35}{12}, k = \frac{1}{12} + i \frac{35}{12}

求解步骤

21 k^{2} + 4 k = - 3 + 6 k + 9 k^{2}

交换两边

- 3 + 6 k + 9 k^{2} = 21 k^{2} + 4 k

将

4 k

para o lado esquerdo

9 k^{2} + 2 k - 3 = 21 k^{2}

将

21 k^{2}

para o lado esquerdo

- 12 k^{2} + 2 k - 3 = 0

使用求根公式求解

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 12 ) ( - 3 )}{2 ( - 12 )}

化简

2^{2} - 4 (- 12) (- 3) : 235 i

k_{1, 2} = \frac{- 2 \pm 2 35 i}{2 ( - 12 )}

将解分隔开

k_{1} = \frac{- 2 + 2 35 i}{2 ( - 12 )}, k_{2} = \frac{- 2 - 2 35 i}{2 ( - 12 )}

k = \frac{- 2 + 2 35 i}{2 ( - 12 )} : \frac{1}{12} - i \frac{35}{12}

k = \frac{- 2 - 2 35 i}{2 ( - 12 )} : \frac{1}{12} + i \frac{35}{12}

二次方程组的解是:

k = \frac{1}{12} - i \frac{35}{12}, k = \frac{1}{12} + i \frac{35}{12}

作图

流行的例子

3 a^{2} - 27 = 0

x^{2} - 8 x = 9 x - 12

4x-10(-x-1)=6(x-2)6(x-2)

4 x - 10 (- x - 1) = 6 (x - 2) 6 (x - 2)

solvefor x,xy^2+x^2+4y-4=0

so l v e f or x, x y^{2} + x^{2} + 4 y - 4 = 0

6 x^{2} - 3 x + 9 = 0