展开 (f(x+h)-x^2-6x+3)/h

解答

展开

\frac{f ( x + h ) - x ^{2} - 6 x + 3}{h}

\frac{f x}{h} + f - \frac{x ^{2}}{h} - \frac{6 x}{h} + \frac{3}{h}

求解步骤

\frac{f ( x + h ) - x ^{2} - 6 x + 3}{h}

乘开

f (x + h) - x^{2} - 6 x + 3 : f x + f h - x^{2} - 6 x + 3

= \frac{f x + f h - x ^{2} - 6 x + 3}{h}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{f x + f h - x ^{2} - 6 x + 3}{h} = \frac{f x}{h} + \frac{f h}{h} - \frac{x ^{2}}{h} - \frac{6 x}{h} + \frac{3}{h}

= \frac{f x}{h} + \frac{f h}{h} - \frac{x ^{2}}{h} - \frac{6 x}{h} + \frac{3}{h}

消掉

\frac{f h}{h} : f

= \frac{f x}{h} + f - \frac{x ^{2}}{h} - \frac{6 x}{h} + \frac{3}{h}

e x p an d (- 8 x + 7 y) (4 x + 2 y) \Rightarrow

e x p an d (- 6, - 2) y (- 3, 2)

e x p an d 0 (x - (- 2))

e x p an d A (- 3, - 4) y B (- 5, 6)

e x p an d (5 x^{2} - 8 x) e^{x}