展开 2(e^x(Acos(x)+Bsin(x)))

解答

展开

2 (e^{x} (A cos (x) + B sin (x)))

2 A e^{x} cos (x) + 2 B e^{x} sin (x)

求解步骤

2 (e^{x} (A cos (x) + B sin (x)))

去除括号:

(a) = a

= 2 e^{x} (A cos (x) + B sin (x))

使用分配律:

a (b + c) = ab + a c

a = 2 e^{x}, b = A cos (x), c = B sin (x)

= 2 e^{x} A cos (x) + 2 e^{x} B sin (x)

= 2 A e^{x} cos (x) + 2 B e^{x} sin (x)

e x p an d \frac{( - 6 + 3 y + 4 x ) ( 18 + 3 y - 4 x )}{9}

e x p an d 3 x^{2} y d x + (y + x^{3}) d x

e x p an d 3 x^{2} y d x + (y + x^{3}) d y

e x p an d j (z - e^{T (j - 1)}) (z - e^{- T (j + 1)})

e x p an d e^{2 x} (2 + e^{x})