化简 e^{i(x+y)}

解答

化简

e^{i (x + y)}

cos (x + y) + i sin (x + y)

求解步骤

e^{i (x + y)}

使用虚数运算法则:

e^{ia} = cos (a) + i sin (a)

= cos (x + y) + i sin (x + y)

e x p an d \frac{sin ( x ( x + y ) )}{x + y}

e x p an d \frac{( a + h ) ^{3}}{h}

e x p an d \frac{5 ( y + 3 )}{3}

e x p an d (4 a - b) e^{3}

e x p an d P (- 9, - 4) Q (- 4, - 5)