What are the solutions to the equation -x^2+9x-14=0 ?

The solutions to the equation -x^2+9x-14=0 are x=2,x=7

Find the zeros of -x^2+9x-14=0

The zeros of -x^2+9x-14=0 are x=2,x=7

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- x^{2} + 9 x - 14 = 0

x = 2, x = 7

Solution steps

- x^{2} + 9 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) ( - 14 )}{2 ( - 1 )}

9^{2} - 4 (- 1) (- 14) = 5

x_{1, 2} = \frac{- 9 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 5}{2 ( - 1 )}, x_{2} = \frac{- 9 - 5}{2 ( - 1 )}

x = \frac{- 9 + 5}{2 ( - 1 )} : 2

x = \frac{- 9 - 5}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = 2, x = 7

(x + 8)^{2} = 9

3 x^{2} - 6 x - 12 = 0

n^{2} + 9 n - 400

8 k^{2} - 6 k - 9

What are the solutions to the equation -x^2+9x-14=0 ?
The solutions to the equation -x^2+9x-14=0 are x=2,x=7
Find the zeros of -x^2+9x-14=0
The zeros of -x^2+9x-14=0 are x=2,x=7