What are the solutions to the equation 7q^2+7q-14=0 ?

The solutions to the equation 7q^2+7q-14=0 are q=1,q=-2

Find the zeros of 7q^2+7q-14=0

The zeros of 7q^2+7q-14=0 are q=1,q=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 q^{2} + 7 q - 14 = 0

q = 1, q = - 2

Solution steps

7 q^{2} + 7 q - 14 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 7 ( - 14 )}{2 \cdot 7}

7^{2} - 4 \cdot 7 (- 14) = 21

q_{1, 2} = \frac{- 7 \pm 21}{2 \cdot 7}

Separate the solutions

q_{1} = \frac{- 7 + 21}{2 \cdot 7}, q_{2} = \frac{- 7 - 21}{2 \cdot 7}

q = \frac{- 7 + 21}{2 \cdot 7} : 1

q = \frac{- 7 - 21}{2 \cdot 7} : - 2

The solutions to the quadratic equation are:

q = 1, q = - 2

699

\frac{5}{2 x - 1} = \frac{1}{x - 2}

0 = - 3 x^{2} + 5 x + 9

3 + \frac{1}{x} \leq 3

x^{2} - 4 x \geq 0

What are the solutions to the equation 7q^2+7q-14=0 ?
The solutions to the equation 7q^2+7q-14=0 are q=1,q=-2
Find the zeros of 7q^2+7q-14=0
The zeros of 7q^2+7q-14=0 are q=1,q=-2