erweitern ((x+2)(3x+1))/2

Lösung

erweitern

\frac{( x + 2 ) ( 3 x + 1 )}{2}

\frac{3 x ^{2}}{2} + \frac{7 x}{2} + 1

Schritte zur Lösung

\frac{( x + 2 ) ( 3 x + 1 )}{2}

Multipliziere aus

(x + 2) (3 x + 1) : 3 x^{2} + 7 x + 2

= \frac{3 x ^{2} + 7 x + 2}{2}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 7 x + 2}{2} = \frac{3 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

= \frac{3 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

Wende Regel an

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{3 x ^{2}}{2} + \frac{7 x}{2} + 1

e x p an d \frac{x}{( x ^{2} + 4 ) ( 2 s + 1 )}

e x p an d (5 x) (x^{2})

e x p an d \frac{x ^{3} - 3 x + 10}{( 3 - x ) x ^{2}}

e x p an d \frac{4 x}{( x - 1 ) ( x + 1 )}

e x p an d b_{0} (a_{1} + 1, \frac{1}{a _{0}})