erweitern \forall x(x^2-x\ne 1)

Lösung

erweitern

\forall x (x^{2} - x \neq = 1)

\forall x^{3} - \forall x^{2} \neq = 1

Schritte zur Lösung

\forall x (x^{2} - x \neq = 1)

= \forall x (x^{2} - 1 \neq = x)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = \forall x, b = x^{2}, c = x \neq = 1

\forall x x^{2} - \forall xx \neq = 1

\forall x^{2} x - \forall xx \neq = 1

Multipliziere aus

\forall x^{2} x - \forall xx : \forall x^{3} - \forall x^{2}

\forall x^{3} - \forall x^{2} \neq = 1

e x p an d \frac{100}{( 1 - x \cdot 10 ) ^{2}}

e x p an d e^{2 (x - 3)} + e^{- 2 (x - 3)}

e x p an d \frac{( 2 x - 6 ) ( x + 4 )}{( x + 5 ) ( x - 2 )}

e x p an d (e^{x} - 1) (e^{x} - x)^{2}

e x p an d (2 x^{2} + 3 x - 3) e^{x}