展开 (2x^2-3x-20)^5

解答

展开

(2 x^{2} - 3 x - 20)^{5}

32 x^{10} - 240 x^{9} - 880 x^{8} + 8520 x^{7} + 11210 x^{6} - 122643 x^{5} - 112100 x^{4} + 852000 x^{3} + 880000 x^{2} - 2400000 x - 3200000

求解步骤

(2 x^{2} - 3 x - 20)^{5}

(2 x^{2} - 3 x - 20)^{5} = (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20)

= (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20)

乘开

(2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) (2 x^{2} - 3 x - 20) : 32 x^{10} - 240 x^{9} - 880 x^{8} + 8520 x^{7} + 11210 x^{6} - 122643 x^{5} - 112100 x^{4} + 852000 x^{3} + 880000 x^{2} - 2400000 x - 3200000

= 32 x^{10} - 240 x^{9} - 880 x^{8} + 8520 x^{7} + 11210 x^{6} - 122643 x^{5} - 112100 x^{4} + 852000 x^{3} + 880000 x^{2} - 2400000 x - 3200000

e x p an d \frac{( x ^{3} - 4 ) ^{6}}{64 x ^{6}}

e x p an d \frac{( x + 4 ) ( x - 5 )}{( x + 6 ) ( 3 x - 2 )}

e x p an d \frac{4 x ^{2} - 1}{( x + 5 ) ( x + 3 )}

e x p an d \frac{x ( 5 ln ( x ) - 1 )}{25}

e x p an d \frac{1}{x ( x ^{2} - x + 1 )}