展开-4(-(piM)/2+5(2pi-4))

解答

展开

- 4 (- \frac{π M}{2} + 5 (2 π - 4))

2 π M - 40 π + 80

求解步骤

- 4 (- \frac{π M}{2} + 5 (2 π - 4))

使用分配律:

a (b + c) = ab + a c

a = - 4, b = - \frac{π M}{2}, c = 5 (2 π - 4)

= - 4 (- \frac{π M}{2}) + (- 4) \cdot 5 (2 π - 4)

使用加减运算法则

- (- a) = a, + (- a) = - a

= 4 \cdot \frac{π M}{2} - 4 \cdot 5 (2 π - 4)

化简

4 \cdot \frac{π M}{2} - 4 \cdot 5 (2 π - 4) : 2 π M - 40 π + 80

= 2 π M - 40 π + 80

e x p an d \frac{2 x - 5}{( x - 1 ) ( x - 4 )}

\frac{d ^{2}}{d x ^{2}} ((y) (4 x - 1))

e x p an d \frac{2 x}{( x - 2 ) ^{2}}

e x p an d (2 x + 4 y = - 12) \cdot (- 5)

s im pl i f y (e^{i θ} + e^{- i θ})^{6}