展开 (2+x)[\H(x-2)-H[x-3]]

解答

展开

(2 + x) [H (x - 2) - H [x - 3]]

- x^{2} H + x H + x H (x - 2) + 2 H (x - 2) + 6 H

求解步骤

(2 + x) [H (x - 2) - H [x - 3]]

使用分配律:

a (b + c) = ab + a c

a = [H (x - 2) - H [x - 3]], b = 2, c = x

= [H (x - 2) - H [x - 3]] \cdot 2 + [H (x - 2) - H [x - 3]] x

= 2 [H (x - 2) - H [x - 3]] + x [H (x - 2) - H [x - 3]]

化简

2 [H (x - 2) - H [x - 3]] + x [H (x - 2) - H [x - 3]] : - x^{2} H + x H + x H (x - 2) + 2 H (x - 2) + 6 H

= - x^{2} H + x H + x H (x - 2) + 2 H (x - 2) + 6 H

e x p an d (d t + 3 t^{4} d w)^{2}

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e x p an d \frac{( 5 - 2 x ) ^{2}}{π} - x^{2}

e x p an d (l, m, n) (1, - 4, - 2)

e x p an d 5^{3} \cdot 8^{4}