erweitern ((20d-at)^2)/(25t^2)

Lösung

erweitern

\frac{( 20 d - a t ) ^{2}}{25 t ^{2}}

\frac{16 d ^{2}}{t ^{2}} - \frac{8 d a}{5 t} + \frac{a ^{2}}{25}

Schritte zur Lösung

\frac{( 20 d - a t ) ^{2}}{25 t ^{2}}

(20 d - a t)^{2} = 400 d^{2} - 40 d a t + a^{2} t^{2}

= \frac{400 d ^{2} - 40 d a t + a ^{2} t ^{2}}{25 t ^{2}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{400 d ^{2} - 40 d a t + a ^{2} t ^{2}}{25 t ^{2}} = \frac{400 d ^{2}}{25 t ^{2}} - \frac{40 d a t}{25 t ^{2}} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

= \frac{400 d ^{2}}{25 t ^{2}} - \frac{40 d a t}{25 t ^{2}} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

Teile die Zahlen:

\frac{400}{25} = 16

= \frac{16 d ^{2}}{t ^{2}} - \frac{40 d a t}{25 t ^{2}} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

Streiche

\frac{40 d a t}{25 t ^{2}} : \frac{8 d a}{5 t}

= \frac{16 d ^{2}}{t ^{2}} - \frac{8 d a}{5 t} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

Streiche

\frac{a ^{2} t ^{2}}{25 t ^{2}} : \frac{a ^{2}}{25}

= \frac{16 d ^{2}}{t ^{2}} - \frac{8 d a}{5 t} + \frac{a ^{2}}{25}

e x p an d \frac{( - 5 + x ) ( 5 + x )}{4 + 5 x}

e x p an d \frac{s + 1}{s ( s ^{2} + 1 )}

e x p an d - 4 (x - 3 y = 4)

e x p an d \frac{( 3 s + 4 ) ^{3}}{9}

e x p an d \frac{2 - x ( x + 2 + 2 )}{x - 2}