erweitern (2+x)[\H(x-2)-H[x-3]]yy_{2}

Lösung

erweitern

(2 + x) [H (x - 2) - H [x - 3]] y y_{2}

- x^{2} Hy y_{2} + x Hy y_{2} + x y y_{2} H (x - 2) + 2 y y_{2} H (x - 2) + 6 Hy y_{2}

Schritte zur Lösung

(2 + x) [H (x - 2) - H [x - 3]] y y_{2}

= y y_{2} (2 + x) [H (x - 2) - H [x - 3]]

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = [H (x - 2) - H [x - 3]] y y_{2}, b = 2, c = x

= [H (x - 2) - H [x - 3]] y y_{2} \cdot 2 + [H (x - 2) - H [x - 3]] y y_{2} x

= 2 y y_{2} [H (x - 2) - H [x - 3]] + x y y_{2} [H (x - 2) - H [x - 3]]

Vereinfache

2 y y_{2} [H (x - 2) - H [x - 3]] + x y y_{2} [H (x - 2) - H [x - 3]] : - x^{2} Hy y_{2} + x Hy y_{2} + x y y_{2} H (x - 2) + 2 y y_{2} H (x - 2) + 6 Hy y_{2}

= - x^{2} Hy y_{2} + x Hy y_{2} + x y y_{2} H (x - 2) + 2 y y_{2} H (x - 2) + 6 Hy y_{2}

e x p an d (2 p - 0.01 p^{2}) d p

e x p an d \frac{( 200 - x ) ^{6}}{( 80 - x ) ^{3}}

e x p an d \frac{( 4 - 2 x ^{2} ) ^{2}}{16 - 3 x}

e x p an d (2 x - 2 x - 3)^{7}

e x p an d (4 e^{2 x} + 4 x e^{2 x}) (2 e^{2 x}) (x)