展开 y(2xe^{xy}+e^{xy}yx^2)

解答

展开

y (2 x e^{x y} + e^{x y} y x^{2})

2 e^{y x} y x + e^{y x} y^{2} x^{2}

求解步骤

y (2 x e^{x y} + e^{x y} y x^{2})

= y (2 e^{y x} x + e^{y x} y x^{2})

使用分配律:

a (b + c) = ab + a c

a = y, b = 2 x e^{x y}, c = e^{x y} y x^{2}

= y \cdot 2 x e^{x y} + y e^{x y} y x^{2}

= 2 e^{y x} y x + e^{y x} yy x^{2}

e^{y x} yy x^{2} = e^{y x} y^{2} x^{2}

= 2 e^{y x} y x + e^{y x} y^{2} x^{2}

e x p an d ln (x - 3) (x + 3)

e x p an d - \frac{g ( 5 u - 4 )}{9}

e x p an d, 2 (w + 5) - 5 w

e x p an d \frac{16}{( 3 x + 3 ) ( x + 1 )}

e x p an d \frac{1}{2 ( x - 4 ) ^{2}}